Problem Statement
The Sieve of Erathosthenes is an ancient method used to find all prime numbers between 2 and a given upper bound maxNum, inclusive. It works like this:
make a list of all numbers between 2 and maxNum, inclusive
for x = 2 to maxNum
if x is not scratched
for y = 2 to maxNum/x
if x*y is not scratched, scratch x*y
end for
end if
end for
In this fashion, every composite number in the range will get scratched while every prime number will remain unscratched. Return the last number which gets scratched when the Sieve of Eratosthenes is run with the given maxNum.
Definition
- Class:
- SieveOfEratosthenes
- Method:
- lastScratch
- Parameters:
- int
- Returns:
- int
- Method signature:
- int lastScratch(int maxNum)
- (be sure your method is public)
Constraints
- maxNum will be between 4 and 2000000000 (2*109), inclusive.
Examples
18
Returns: 15
When x=2, the numbers 4, 6, 8, 10, 12, 14, 16, and 18 are scratched. When x=3, only 9 and 15 are scratched (other multiples like 6 and 12 were already scratched in a previous step). For x=5,7,11,13 and 17, there are no new scratches. Therefore, the answer is 15.5
Returns: 4
2, 3 and 5 are all primes, so the only scratched number is 4.100
Returns: 91
400
Returns: 361