Problem Statement
An overlapping concatenation of an ordered pair of Strings (A, B) is a String S such that A is a prefix of S and B is a suffix of S. A shortest overlapping concatenation (SOC) of (A, B) is an overlapping concatenation whose length is as small as possible. For example, if A is "cabab" and B is "ababc", the shortest overlapping concatenation is "cababc" (all quotes for clarity). You are given two Strings A and B, in which some of the characters are known and some are unknown. Each character in A and B will be a lowercase letter ('a' - 'z') if it is known or '*' if it is unknown.
Assuming that each unknown character will be selected uniformly at random from the characters contained in alphabet, return the expected length of the shortest overlapping concatenation of A and B.
Assuming that each unknown character will be selected uniformly at random from the characters contained in alphabet, return the expected length of the shortest overlapping concatenation of A and B.
Definition
- Class:
- OverlappingConcatenation
- Method:
- shortestExpected
- Parameters:
- String, String, String
- Returns:
- double
- Method signature:
- double shortestExpected(String A, String B, String alphabet)
- (be sure your method is public)
Constraints
- alphabet will contain between 1 and 26 lowercase letters ('a' - 'z'), inclusive.
- The characters in alphabet will be distinct.
- A and B will contain between 1 and 32 characters, inclusive.
- A and B will contain the same number of characters.
- Each character in A and B will either be contained in alphabet or it will be '*'.
Examples
"aa*aa"
"a*aaa"
"ab"
Returns: 7.0
The 4 equal-probability possibilities for the shortest overlapping concatenation (SOC) are as follows: A | B | SOC aaaaa | aaaaa | aaaaa aabaa | aaaaa | aabaaaaa aaaaa | abaaa | aaaaabaaa aabaa | abaaa | aabaaa The result is therefore (5 + 8 + 9 + 6) / 4 = 7."**"
"**"
"ab"
Returns: 3.125
There are 16 possibilities for A and B. Of these, 4 give a SOC of length 2; 6 give a SOC of length 3; and 6 give a SOC of length 4. The answer is therefore (4*2 + 6*3 + 6*4) / 16 = 3.125."**a*cd"
"cde***"
"abcdefghijklmnopqrstuvwxyz"
Returns: 10.0
It makes no difference what the unknown characters are; the SOC is always the same length."h*phz*"
"hzph*p"
"zph"
Returns: 10.555555555555557