Problem Statement
Consider all the positive integers with the property that their digits alternate between being odd and even. The sequence of these numbers begins as follows:
1, 2, ..., 9, 10, 12, 14, 16, 18, 21, 23, 25, 27, 29, 30, 32, ..., 96, 98, 101, 103, 105, 107, 109, 121, 123, ..., 187, 189, 210, 212, ...
Given K, which is the K-th number in this sequence?
Definition
- Class:
- AlternateOddEven
- Method:
- kth
- Parameters:
- long
- Returns:
- long
- Method signature:
- long kth(long K)
- (be sure your method is public)
Notes
- The answer for each valid test case is guaranteed to fit into a signed 64-bit integer.
Constraints
- K will be between 1 and 10^11, inclusive.
Examples
9
Returns: 9
The first nine numbers in our sequence (positions 1 to 9) are the nine one-digit positive integers.15
Returns: 21
The next six numbers (in positions 10 to 15) are 10, 12, 14, 16, 18, 21.62
Returns: 125
100
Returns: 290