NumberofFiboCalls

Look at the following pseudo-code, which computes the n-th Fibonacci number:

int fibonacci(int n)
	begin
	if n equals 0
		begin
		print(0)
		return 0
		end
	if n equals 1
		begin
		print(1)
		return 1
		end
	return fibonacci(n - 1) + fibonacci(n - 2)
	end

For example, if one calls fibonacci(3), then the following will happen:

• fibonacci(3) calls fibonacci(2) and fibonacci(1) (the first call).
• fibonacci(2) calls fibonacci(1) (the second call) and fibonacci(0).
• The second call of fibonacci(1) prints 1 and returns 1.
• fibonacci(0) prints 0 and returns 0.
• fibonacci(2) gets the results of fibonacci(1) and fibonacci(0) and returns 1.
• The first call of fibonacci(1) prints 1 and returns 1.
• fibonacci(3) gets the results of fibonacci(2) and fibonacci(1) and returns 2.

We want to know how many times '0' and '1' will be printed for a given n. You are to return a int[] which contains exactly two elements. The first and second elements of the return value must be equal to the number of times '0' and '1', respectively, will be printed during a fibonacci(n) call.