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SRM6 Apr 2005
SRM 237

MirrorPath

Problem statement, definition, constraints, and public examples.

Problem Statement

NOTE: This problem statement contains an image that may not display properly if viewed outside of the applet.

You will be given the map of a maze containing mirrors. There will be exactly two openings on the boundary of the maze. A laser shined through one opening will reflect off the mirrors and exit through the other opening. You are to write a method that outputs the map of the maze with the laser's path drawn in it.

Mirrors are always at a 45-degree angle to the axis of the maze, and deflect the laser at a right angle. The maze will consist of walls ('#'), open spaces ('.'), and mirrors ('/' and '`') arranged on a regular grid. Your method should replace some or all of the '.' characters in the map with '|', '-', and '+' characters, indicating the open spaces where the laser travels vertically, travels horizontally, and crosses its own path, respectively.

For example, given the following three mazes:


    #######    #######    #######
    ##....#    ##/..`#    ##/..`#
    ##.##.#    ##.##.#    ##.##.#
    ##.##.#    ##.##.#    ##.##.#
    ..`...#    ...../#    ../../#
    ##.####    ##.####    ##.####
    ##.####    ##.####    ##.####

the laser would be reflected as shown in the following figure:

and the solutions for each of these three examples are as follows:


    #######    #######    #######
    ##....#    ##/--`#    ##/--`#
    ##.##.#    ##|##|#    ##|##|#
    ##.##.#    ##|##|#    ##|##|#
    --`...#    --+--/#    --/--/#
    ##|####    ##|####    ##|####
    ##|####    ##|####    ##|####

Note that the laser can bounce of both sides of the same mirror.

Definition

Class:
MirrorPath
Method:
path
Parameters:
String[]
Returns:
String[]
Method signature:
String[] path(String[] map)
(be sure your method is public)

Notes

  • Since '\' is a special character, we will use the '/' (forward slash) and '`' (back quote) characters to indicate mirrors in the input.

Constraints

  • map will contain between 3 and 50 elements, inclusive.
  • The length of each element of map will be the same, and be between 3 and 50, inclusive.
  • map will contain only the characters '#', '.', '/', and '`'.
  • Exactly 2 characters on the boundary of map will be '.'. All other characters on the boundary will be '#'.
  • The characters in the four corners of map will be '#'.
  • The map will be such that if a laser is shined through one opening on the boundary, it will exit through the other opening.

Examples

  1. { "#.#",
      "#.#",
      "#.#" }
    
    Returns: {"#|#", "#|#", "#|#" }
  2. { "############",
      "#######/....",
      "######//####",
      "#####//#####",
      "####//######",
      "..../#######",
      "############" }
    Returns: {"############", "#######/----", "######//####", "#####//#####", "####//######", "----/#######", "############" }
  3. { "#######",
      "##/..`#",
      "##.##.#",
      "##.##.#",
      "...../#",
      "##.####",
      "##.####" }
    Returns: {"#######", "##/--`#", "##|##|#", "##|##|#", "--+--/#", "##|####", "##|####" }
    This is the second example in the problem statement.
  4. { "###########.#",
      "#/........./.",
      "#.#########.#",
      "#`........./#",
      "#############" }
    Returns: {"###########|#", "#/---------/-", "#|#########|#", "#`---------/#", "#############" }
    This is similar to the third example in the problem statement.
  5. { "########.##",
      "#./......`#",
      "#../.`....#",
      "#.`...../.#",
      "#....`.../#",
      "###.#######" }
    Returns: {"########|##", "#./-----+`#", "#.|/-`..||#", "#.`+-+--/|#", "#..|.`---/#", "###|#######" }
  6. { "##.########",
      "#.........#",
      "..`.`.....#",
      "#..`......#",
      "#.`.`.`...#",
      "#....`....#",
      "#...`.`.`.#",
      "#.........#",
      "#.....`./.#",
      "#.........#",
      "###########" }
    Returns: {"##|########", "#.|.......#", "--`-`.....#", "#.|`|.....#", "#.`-`-`...#", "#...|`|...#", "#...`-`-`.#", "#.....|.|.#", "#.....`-/.#", "#.........#", "###########" }
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