Problem Statement
You are given a int[] data, and you must order the elements of data such that no two consecutive elements have consecutive values. In other words, result[i] + 1 != result[i + 1] for all i, where 0 <= i < n-1, and n is the number of elements in data. If more than one ordering exists, return the one that comes first lexicographically.
Definition
- Class:
- WeirdSort
- Method:
- sortArray
- Parameters:
- int[]
- Returns:
- int[]
- Method signature:
- int[] sortArray(int[] data)
- (be sure your method is public)
Constraints
- data will contain between 1 and 50 elements, inclusive.
- Each element of data will be between 0 and 1000, inclusive.
Examples
{1, 2}Returns: {2, 1 }Only one possible ordering exists.{1, 2, 3}Returns: {1, 3, 2 }There are only three possible orderings: {1, 3, 2}, {2, 1, 3} and {3, 2, 1}. The first one is lexicographically smallest.{1, 1, 1, 1, 2, 2, 2, 2, 2}Returns: {2, 2, 2, 2, 2, 1, 1, 1, 1 }All 2's should be before 1's.{1, 2, 3, 4, 5, 6}Returns: {1, 3, 2, 4, 6, 5 }{1, 1, 2, 2, 3, 3}Returns: {1, 1, 3, 3, 2, 2 }