Problem Statement
You wish to build three watchtowers to overlook several points of interest. The points of interest are given in the int[]s x and y, where each element of x and the corresponding element of y represent the coordinates of a single point of interest.
Each of the three watchtowers has a field of view that is the same in all directions. The viewing distance of each of the three watchtowers is given in the int[] view, so the i-th watchtower can see all points which are located not further than view[i] units from it. Assuming optimal placement, return the maximum number of points of interest that are within view of at least one of the watchtowers.
Definition
- Class:
- ThreeWatchtowers
- Method:
- maximumCoverage
- Parameters:
- int[], int[], int[]
- Returns:
- int
- Method signature:
- int maximumCoverage(int[] x, int[] y, int[] view)
- (be sure your method is public)
Notes
- Even though points of interest are restricted to a given area, the watchtowers themselves may be located outside of that area, and do not necessarily have to be placed on lattice points.
- A watchtower can see a point exactly on the edge of its field of view. Thus, a watchtower at (0, 0) with a radius of 2 could see a point at (0, 2).
Constraints
- x and y will each contain between 1 and 20 elements, inclusive.
- x and y will each contain the same number of elements.
- Each element of x and y will be between 0 and 20, inclusive.
- view will contain exactly 3 elements.
- Each element of view will be between 1 and 20, inclusive.
Examples
{0, 10, 20}{15, 16, 20}{1, 1, 1}Returns: 3
Even though the watchtowers can't see very far, with only three points of interest, it is trivial to cover them all.{0, 1, 10, 20, 15, 14}{1, 0, 10, 20, 18, 12}{2, 2, 2}Returns: 4
The first two points are close enough together to be covered by a single watchtower. The other points are too spread out, so the other two towers can each only see a single point.{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}{1, 1, 13}Returns: 10
The first two watchtowers are not really needed, since the last one has a wide enough range to see all 10 points at once.{0, 5, 6, 16, 18, 20}{0, 6, 7, 20, 20, 20}{1, 3, 5}Returns: 6
The first watchtower covers the first point. The second watchtower can cover the next two points. The last three points can be covered by the final tower.{1, 2, 0, 3, 1}{0, 3, 2, 1, 0}{1, 1, 1}Returns: 4
{10, 18, 16, 9, 17, 20, 4, 3, 11, 9}{4, 17, 6, 14, 14, 14, 12, 12, 13, 16}{1, 1, 2}Returns: 7