Problem Statement
Given a positive integer N with at least two digits, we can define magic(N) as follows: Write N as a string of decimal digits. Now, for each two consecutive digits, compute their difference (a non-negative number less than ten), and write it down. In this way you'll obtain a new number, possibly with leading zeroes. Drop unnecessary leading zeroes if there are any.
For example, magic(5913)=482, magic(1198)=081=81, and magic(666)=00=0.
For any number N the sequence: N, magic(N), magic(magic(N)), ... will sooner or later terminate with a single-digit number. This final value is called the magic fingerprint of N.
For example, for N=5913 we get the sequence: 5913, 482, 46, 2. Therefore the magic fingerprint of 5913 is 2.
There are not too many numbers with the magic fingerprint seven (7). These numbers are considered lucky.
Write a method that will compute the count of lucky numbers between A and B, inclusive.
Definition
- Class:
- MagicFingerprint
- Method:
- countLuckyNumbers
- Parameters:
- int, int
- Returns:
- int
- Method signature:
- int countLuckyNumbers(int A, int B)
- (be sure your method is public)
Constraints
- B will be between 1 and 1,000,000,000, inclusive.
- A will be between 1 and B, inclusive.
Examples
1
9
Returns: 1
The only single-digit lucky number is, of course, the lucky number seven.1
100
Returns: 6
There are five two-digit lucky numbers: 18, 29, 70, 81, and 92.1198
1198
Returns: 1
The number 1198 is lucky. The corresponding sequence is: 1198, 81, 7.1223
1299
Returns: 0
This range contains no lucky numbers.999999930
1000000000
Returns: 2
The two lucky numbers in this range are 999,999,980 and 999,999,992.100000
1000000000
Returns: 159720
The largest output is obviously not much larger.