Problem Statement
A partition of the number n is the set of numbers that all sum up to n. For example, we have 5 different partitions of 4: {1, 1, 1, 1}, {1, 1, 2}, {1, 3}, {2, 2}, {4}. If we sort all the numbers within each set, we can treat each partition as a sorted list of numbers and so introduce a lexicographic order on all partitions. For example, the partitions of 4 mentioned before are given in order. You are given ints n and k. Determine all the partitions of n, sort them in lexicographical order, and return a int[] containing the k-th one (k is a 1-based index). If there are not enough partitions of n, return an empty int[].
Definition
- Class:
- NumberPartition
- Method:
- kthPartition
- Parameters:
- int, int
- Returns:
- int[]
- Method signature:
- int[] kthPartition(int n, int k)
- (be sure your method is public)
Notes
- The lexicographical order is exactly the same as in a dictionary. A int[] A is lexicographically before a int[] B if there exists an integer i such that A[i] < B[i] and A[j] = B[j] for all j < i or if A is a proper prefix of B.
Constraints
- n will be between 1 and 50, inclusive.
- k will be between 1 and 1000000, inclusive.
Examples
4
1
Returns: {1, 1, 1, 1 }Example from the problem statement.4
3
Returns: {1, 3 }17
123
Returns: {1, 1, 1, 3, 3, 3, 5 }12
1234
Returns: { }There are less then 1234 partitions of 12.